WebMaster  Tuesday, October 29, 2002  08:20 pm Megalithic Yard and Hydrogen Radius At the following websites Prof. Alexander Thom gives the megalithic yard as 2.72 feet or 32.64 inches. A meter is 39.37 inches. The conversion of the two measuring forms is through the radius of the hydrogen atom (.037 pm) and the fine structure constant (1/137.036000986 = a(em) as follows: [10 ^ [((39.37in.32.64in.)/.037)180]] / 6.66 = sqrt 137.036000986 or as: [[[log ((sqrt 1/a(em)) * 6.66)] + 180] *.037 ] + 32.64in. = 39.3699999988in. 180 is of course 1/2 part of the radian equation :180/Pi = radian Also ...log((sqrt137.036000986 * 6.66) is modulo to the "collective unconscious" constant: 144/37= 3.891891891 J.Iuliano EARTH MYSTERIES: Alexander Thom ... Thom also undertook the project of accurately surveying and carefully measuring ... His discovery of what he called the megalithic yard (2.72 feet ... witcombe.sbc.edu/earthmysteries/EMThom.html ... Thom also undertook the project of accurately surveying and carefully measuring ... His discovery of what he called the "megalithic yard" (2.72 feet ... www.britannia.com/wonder/thom.html  17k  Cached  Similar pages megalithicmeasures ... Because Thom tried to pin down the Megalithic yard ... Although he knew that a measure of around 2.72 feet was the basis of their system, in terms ... www.secretacademy.com/pages/megalithicmeasures.htm Brief description ... He stated, after much deliberation, that the value of the megalithic yard was 2.72ft, although there were variations. Had Thom been able to prove irrefutably ... www.secretacademy.com/pages/briefdescription.htm Southwestern Archaeology  Messages ... Yard" Hi Clive  In Thom's "Megalithic Sites in Britain" he devotes Ch. 5 to the megalithic unit of length, and argues for a "megalithic yard" = 2.72 +/ ... www.swanet.org/zarchives/gotcaliche/alldailyeditions/ 96may/message170.html ... CountZ.com CountZ.com Megalithic Yard Surprises  Megalithic Yard ... Counter added June 2002) If Professor Thom in ... a unit equivalent to his stated 2.72 ... members.tripod.com/hew_frank Megalithic Yard Surprises ... FOOT', THERE HAS BEEN A MEGALITHIC YARD 7 ... were used, which he called a Megalithic ... additions page for Arabian measures.) If Thom's ... Would the quantum of 2.72 ft. ... members.tripod.com/hew_frank/id19.htm Orkneyjar  Professor Alexander Thom ... Thom's discovery was what he termed "the megalithic yard"  a measurement of 2.72 feet, or 0.83 metres  that suggests the megalithic builders of these stone ... www.orkneyjar.com/history/monoliths/thom.htm ... this, I followed in the footsteps of the late Professor Alexander Thom, who discovered and proved the existence of the 'Megalithic Yard' (MY), a unit of 2.72 ft ... www.footrule.org/Lunations.htm Thom spent his retirement from Oxford surveying and studying megalithic ... He found that a unit of 2.72 feet was in ... to 30% of sites also using a half yard ... www.robertlomas.com/osf/megpres/tsld028.htm ... 2.72 is also the length in feet of Alexander Thom's Megalithic Yard. McClain, Ernest G., 1978. The Myth of Invariance. Boulder & London: Shambhala. ... www.geomancy.org/webworking/bibliography/ bibliography3.html J. Iuliano
Jerry Iuliano   Email: JerryIuliano@aol.com 

WebMaster  Tuesday, October 29, 2002  08:23 pm Golden Section and Feigenbaum The dual systems of angular measure, the Sumerian 360 degrees for one cycle, and angular radian measure...180/Pi = radian = 57.29577951, show their common origin from the Golden Section constant "fractalized" by the Cheops pyramid constructs to derive the finestructure constant , the amplitude for an electron to emit or absorb a photon....1/137.03599976 = a(em). (1+sqrt5)/2 = 1.618033989.... = Golden Section [[[COS^1[[((1+sqrt5)/2)1]/2]]*4] ^ (ht/bl)] / 100 = cos(1/a(em)) height = ht = 486.25611...Churchward/Ramsey ht = 486.256..bl = 763.81 base leg = bl = 763.81 The left side of the equation is measured in cosine of Sumerian 360 degrees (COS); the right side, cosine inverse finestructure...cos1/a(em).. is measured in radians (cos). The Cheops pyramid constructs link the two measuring systems, one ancient (Sumerian) and one modern (radian). Also note the INVERSE cosine form of the Sumerian measure (360 degrees) , versus the cosine INVERSE finestructure constant. The equation proves that the Cheops constructs ht and bl are the equvalent of metric measures since the finestructure constant is a cancelled metric: cos(2*E*h*c/(e^2) = cos 1/(a(em)) 1/(a(em)) = 137.03599976 e = elementary charge Coulombs E = electric constant h = Plancks constant Joules c = speed of light meters /seconds to isolate the Golden Section of Nature transformation to unity : [COS[[(cos1/(a(em))^(bl/ht)]/4] = 1 = unity COS ...Sumerian (360) cos......radian (180/Pi) The Feigenbaum bifurcation constant...4.669201609... is hidden in the transformation equation: [tan^1[1/[[cos 1/(a(em))]^(2*bl/ht)]]] + Pi = 4.669204876..in radians J.Iuliano Sources for Cheops pyramid constructs: FlindersPetrie (1883)....section 144 http://members.optushome.com.au./fmetrol/petrie/C21.html height... = 5776 English inches base leg = 9073 English inches Churchward/Ramsey (1910).... http://www.charm.net/~ces/trade/tback.html height ....= 486.256 English feet base leg = 763.81 English feet Howard Vyse (1830's)..... from the book, The Geometry of Art and Life, by Matila Ghyka,p.22 height.....= 148.2 meters base leg = 232.8 meters
Jerry Iuliano   Email: JerryIuliano@aol.com 

WebMaster  Tuesday, October 29, 2002  08:25 pm 864 And G Minus Two The number 864 has popped up in my studies also. I have refered to it as a Dirac derived constant that represents the anamolous constant the Gfactor which is 1.001159652... To get the Gfactor one uses the ratio 864.0007796/863=1.001159652. The correction factor for 864 is : 864+ [[10^(144/37)]/10^7]=864.0007796 The number 144/37=3.891891891 I refer to as a magic ratio that can create the finestructure constant: (10^(143.9999879/37))/666=137.035999935^(1/2) The magic ratio can also create the 864 form: (144/37)*(666/3)=864 The magic ratio has ancient references such as 1260/666=1.891891891 and 70/37=1.891891891 and the platonic cycle 25920: 25920/6660=3.891891891.. The Egyptians also used this form: Cheops pyramid ht=486.2560047 ft Cheops pyramid base=763.81 ft log[[(10^(486.2560047/763.81))/.37]*666] =3.891891566... Notice that the first half of this equation creates the finestructure constant: (10^(486.2560047/763.81))/.37=137.035999935^(1/2) J.Iuliano
Jerry Iuliano   Email: JerryIuliano@aol.com 

WebMaster  Tuesday, October 29, 2002  08:27 pm 1/Pi Anything having to do with the constituents of 3dimensional reality..proton ,electron, neutron and the amplitude for the exchange of the electron to photon and the transforming of the proton into a neutron (through the electron)...finestructure constant....can be mathematicaly demonstrated as a holographic equation that uses 1/Pi as the mathematical constant... Sephira Malkuth..288^2 , Feigenbaum's constant.. 4.6692043132..(actual 4.669201609), the golden section ...1.618033989 .(exact), the proton..938.271998 mev (exact) , neutron..939.565331307(actual 939.56533 mev ), electron .5109994691 (actual .510998902). These forms are transfered by the solution nodes generated by the diophantine equation...X^n+ Y^n = Z^n. This solution node base modulo equals... e^(Pi+8).... This represents the transference of torus volumne to angular homogeny that is laced in the fine structure constant through the "collective unconscious" and the 288 phenomenon: 82944^(1/PI) = cos 137.036000986 in radians The secret of the 1/Pi phenomenon runs deep as mathematically illustrated here: Feigenbaum = F = 4.6692043132 100/[[tan(FPi)] ^ (1/Pi) ] = 36.7872976666... in radians Sephira Malkuth = 288 sparks from broken vessels 82944 ^ (1/Pi) = 36.787297604... Golden Section = 1+sqrt5/2 = 1.618033989 [[COS^1(sqrt51/ 4)] *1152] ^ (1/Pi) = 36.787297604... in degrees..1152... gematric "to witness" Finestructure constant = 1/137.036000986 [ cos 137.036000986 ] * 100 = 36.7872975633... in radians Proton to electron: [10*938.271998] ^ [(1/Pi) *(.5109994691^ (1/Pi)] = 36.7872976101 cosine torus volumne form using harmonic mean constants..57 and 37: cos[2*(Pi^2)*57*(37.00000000574^2)] = .510998902^(1/Pi) Fermat form:...e^(Pi+8)... angular transition from cosine form to linear modulo using the neutron as energy difference: neutron  proton.... [[sqrt[(e^(Pi+8))]*1/137.036000986]]/10] ^ (1/Pi) = 939.565331307  938.271998 which is exact to 1998 NIST standards for the neutron = 939.56533... The latter equation is of the form of harmonic mean of the solution generators from the Fermat form a.k.a. as the "torquer" (1/57+1/37). This equation creates the angle of transference to linear form: (1/57+1/37) ^ 1 = 2109/94...such that sqrt[(e^(Pi+7.999999879)) * 1/137.036000986] = 2109/94..such that the exact difference between the neuton and the proton as a function of the "torquer" is: (2109/940)^ (1/Pi) = 939.5653313  938.271998 = 1.293333300.. Note the use of 1/Pi in all seven holographic equations. The 1/Pi form also creates the radian version of TOE. J.Iuliano
Jerry Iuliano   Email: JerryIuliano@aol.com 
